Hmmm. The docs are pretty clear that :visible selects elements. What would be the correct value to return here, or are you requesting that it just return a nonsense value without throwing an error? If the window is not visible (e.g., in a browser tab not being shown) should it return false? Should $(new Object).is(":visible") also return false since it is never visible? Why would someone be trying to do this?

The docs also say that $(...) selects elements. So, since $(window) returns cleanly, it seems logical that $(window).is(':visible') should also return cleanly, instead of throwing a javascript error in IE8 since window.style is undefined and then window.style.display crashes IE8.

And your suggestions about the tabs doesn't seem logical, since $(...).is(':visible') doesn't take tabs into account for other elements.

And the time it might be used is if you have some things in an array, perhaps you're not sure what they're going to be, and you want to check if they're visible before doing something.

var things = [window, document, '#title', '.blocks'];

$.each(things, function() {

var items = $(this).is(':visible');

$('#result').after('<p>Vis: ' + items.count + '</p>');

});

So, taking another look, since visible is the opposite of hidden, it seems like $(window).is(':hidden'); should always return false.

Anyways, I just submitted this because I had to work around the problem and someone mentioned that I shouldn't have to work around $(window).is(':visible'); crashing IE8.

Here was my workaround

var visible = !!this[ 'setTimeout' ] || $(this).is(":visible");

Since "this" could be a link, or a div, or the document, or the window, we know that the window is the only element that has the setTimeout method, so that's how we check to see if it's a window first.

Just wanted to help out.

Replying to [comment:2 js@…]:

var things = [window, document, '#title', '.blocks']; $.each(things, function() { var items = $(this).is(':visible'); $('#result').after('<p>Vis: ' + items.count + '</p>'); });

Oops. I was changing things around and that was an old copy/paste. You get the point though...

var things = [window, document, '#title', '.blocks'];
$.each(things, function() {
  var visible = $(this).is(':visible');
}

Replying to [comment:2 js@…]:

Here was my workaround var visible = !!this[ 'setTimeout' ] || $(this).is(":visible");

Sorry, I can't edit my posts. :( Not used to the WikiFormatting.

var visible = !!this[ 'setTimeout' ] || $(this).is(":visible");

This will be fixed in 1.7. #10178 was a similar situation.

However, the fix for this will not actually check if a window or tab is visible, but it will not throw an error. Technically, a window is always visible whether it has focus or not.

Call .is(:visible) on the window or document does not thrown an error in IE. Fixes #10267.

Changeset: 76a84fba94e0fd32b1a6612c71ef09dee39f6666

Could not reproduce.

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