wrapAll() Doesn't Expose Wrapper

[matthew@…]

After using wrapAll() to create a wrapper, there's no way to get a reference to that wrapper (without reselecting, e.g. with an id).

var wrapper = $('<div />');
$('.some-consecutive-elements').wrapAll(wrapper);
wrapper.append('<span>Some new text</span>'); // Will not work because the "wrapper" variable is not actually a reference to the wrapping element. You must perform a new selection to get the wrapping element.

[timmywil]

Thanks for taking the time to contribute to the jQuery project! Please provide a reduced test case on ​http://jsFiddle.net that reproduces the issue experienced to help us assess your ticket. Additionally, test against the jQuery (edge) version to ensure the issue still exists.

[dmethvin]

That's the way the API is documented to work. Just like .clone() selects the clones, not the original elements.