Attribute value selectors containing colons now trigger a syntax error

[kemayo]

Works: $('[foo=bar]')

Syntax error: $('[foo=bar:12]')

This is a regression from jQuery 1.4.4.

Here's it in 1.5: ​http://jsfiddle.net/Yewzw/ And in 1.4.4: ​http://jsfiddle.net/RCHFZ/1/

[anonymous]

I think it's fair that it rejects this, but it *is* a regression.

[kemayo]

Sorry, the title should have stated "unquoted attribute value selectors". (It works fine if you do [foo="bar:12"].)

[jitter]

Thanks for taking the time to contribute to the jQuery project by writing a bug report.

This isn't a regression it was a bug in earlier jQuery versions that got fixed.

Try ​http://jsfiddle.net/jitter/Yewzw/1/ and you will see that [foo=bar:12] isn't a valid CSS selector and neither is it a valid selector in jQuery. You need to fix your code to either quote or espace the attribute value.

The documentation is also pretty clear about these kind of selectors:

​http://api.jquery.com/category/selectors/

If you wish to use any of the meta-characters ( such as !"#$%&'()*+,./:;?@[\]^{`{|}~ ) as a literal part of a name, you must escape the character with two backslashes}

​http://api.jquery.com/category/selectors/attribute-selectors/

Attribute values in selector expressions must be surrounded by quotation marks.

​http://api.jquery.com/attribute-equals-selector/

Quotes are mandatory.

[jitter]

Duplicate of #8229.