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#7940 closed bug (wontfix)

Opened January 10, 2011 06:59PM UTC

Closed January 10, 2011 09:38PM UTC

$('aa').find('bb, cc') includes the wrong elements

Reported by: korinthe Owned by: korinthe
Priority: low Milestone:
Component: selector Version: 1.4.2
Keywords: Cc:
Blocked by: Blocking:

This is only superficially related to #6754. I am not talking about use of the selector() method at all.

$('aa').find('bb,cc') should find all the elements found by $('aa bb') plus those found by $('aa cc'). Instead it finds $('aa bb') plus $('cc'). Not so useful

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Change History (2)

Changed January 10, 2011 07:47PM UTC by rwaldron comment:1

component: unfiledselector
owner: → korinthe
status: newpending

Thanks for taking the time to contribute to the jQuery project! Please provide a reduced jsFiddle test case to help us assess your ticket!

Additionally, test against the latest jQuery release and the jQuery 0 GIT version to ensure the issue still exists. Be Excellent to eachother!

Changed January 10, 2011 09:38PM UTC by addyosmani comment:2

priority: undecidedlow
resolution: → wontfix
status: pendingclosed

Thanks for submitting your ticket. We have reproduced a minimal test case of the code you're talking about here Live Test Case, but have determined that there is no documented case of .find() supporting two comma-separated strings. You are however able to use a sting string with as many comma-separated selector values as you wish as this should be more than adequate for most use cases.