Opened 10 years ago
Closed 10 years ago
#7940 closed bug (wontfix)
$('aa').find('bb, cc') includes the wrong elements
| Reported by: | korinthe | Owned by: | korinthe |
|---|---|---|---|
| Priority: | low | Milestone: | 1.next |
| Component: | selector | Version: | 1.4.2 |
| Keywords: | Cc: | ||
| Blocked by: | Blocking: |
Description
This is only superficially related to #6754. I am not talking about use of the selector() method at all.
$('aa').find('bb,cc') should find all the elements found by $('aa bb') plus those found by $('aa cc'). Instead it finds $('aa bb') plus $('cc'). Not so useful
Change History (2)
comment:1 Changed 10 years ago by
| Component: | unfiled → selector |
|---|---|
| Owner: | set to korinthe |
| Status: | new → pending |
comment:2 Changed 10 years ago by
| Priority: | undecided → low |
|---|---|
| Resolution: | → wontfix |
| Status: | pending → closed |
Thanks for submitting your ticket. We have reproduced a minimal test case of the code you're talking about here Live Test Case, but have determined that there is no documented case of .find() supporting two comma-separated strings. You are however able to use a sting string with as many comma-separated selector values as you wish as this should be more than adequate for most use cases.
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