get nothing by css('borderColor')

[skywine13@…]

hey guys,

I got a problem that I use 1.4.4 version and my code doesn't work.

I tried to set css border color by call .css('borderColor', '...'), it works. but when I used same function .css('borderColor') to get some, I got nothing but .

The same work fine on 1.4.2 and FireFox 3.6.13. (but I need to face another bug: unbind with JS object......)

Is this a bug, or just my fault ???

[jitter]

​test case

[anonymous]

Same thing with css('borderWidth'), even with css('border').

[SLogic]

Some fix here: ​http://bugs.jquery.com/ticket/7871#comment:2 (in the end of post, after "Update"). But it's not extend computedStyle, if FF 3.6 still no values for 'borderWidth'. But there is 'borderRigthWidth' (all 4 sides exists in computedStyle), so this is a way to get borderWidth in FF.

[anonymous]

Yes I have the same problem. Jquery 1.4.4

alert( $(linkid).css("border-color") ); Nothing is returned.

alert( $(linkid).css("borderColor") ); Nothing is returned.

alert( $(linkid).css("background-color") ); rgb(255,255,255) is returned.

[dfens]

this is not a bug.

there are four border each can have different color so you can do:

var x = $("#elem");
alert( x.css("border-left-color") ); 

i think this ticket may be closed.

[john]

Right yeah, you need to using border-*-color.

[noAlvaro]

.css("border-color") return precise values for all the other browsers. For the sake of writing a more cross-compatible jQuery code, I think this ticket should be reopened.