Opened 13 years ago
Closed 13 years ago
#6721 closed bug (invalid)
XHTML IE8 fix doesn't work with jQuery
Reported by: | fazend | Owned by: | |
---|---|---|---|
Priority: | Milestone: | 1.4.3 | |
Component: | unfiled | Version: | 1.4.2 |
Keywords: | Cc: | ||
Blocked by: | Blocking: |
Description
This is my XHTML/PHP file:
<? header('Content-type: application/xhtml+xml')?> <?="<?xml version=\"1.0\" encoding=\"utf-8\"?>"?> <?="<?xml-stylesheet type=\"text/xsl\" href=\"ie-fix.php\"?>"?> <!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Strict//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-strict.dtd"> <html xmlns="http://www.w3.org/1999/xhtml"> <head> <meta http-equiv="Content-Type" content="application/xhtml+xml; charset=utf-8" /> </head> <body> <script type="text/javascript" src="http://ajax.googleapis.com/ajax/libs/jquery/1.4/jquery.min.js"></script> <script type="text/javascript"> $("body").html("test"); </script> </body> </html>
This is the XSL/PHP file (ie-fix.php):
<? header('Content-type: text/xsl')?> <?="<?xml version=\"1.0\" encoding=\"utf-8\"?>"?> <xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform" xmlns="http://www.w3.org/1999/xhtml" version="1.0"> <xsl:output method="xml" encoding="utf-8"></xsl:output> <xsl:template match="/"> <xsl:copy-of select="node()"></xsl:copy-of> </xsl:template> </xsl:stylesheet>
I created it as explained here: http://www.w3.org/MarkUp/2004/xhtml-faq#ie
My code doesn't work in Safari 5.0, the errors I'm getting are:
TypeError: Result of expression 'd.style' [null] is not an object. ReferenceError: Can't find variable: $
Could anyone help, please? Thanks!
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You say it's an IE8 fix but it doesn't work in Safari?
Try the forum first: http://forum.jquery.com
If it turns out to be a bug, reopen with some more details.