Opened 14 years ago
Closed 14 years ago
#4614 closed bug (invalid)
submit bug?
| Reported by: | jpxavier | Owned by: | brandon |
|---|---|---|---|
| Priority: | major | Milestone: | 1.4 |
| Component: | event | Version: | 1.3.2 |
| Keywords: | submit | Cc: | |
| Blocked by: | Blocking: |
Description (last modified by )
<html>
<head>
<script type="text/javascript" src="jquery.js"></script>
<script type="text/javascript">
$(function() {
$("#f1_submit").click(function(){
$("form:form1").submit();
});
$("#f2_submit").click(function(){
$("form:form2").submit();
});
$("#f3_submit").click(function(){
document.form1.submit();
});
});
</script>
</head>
<body>
<form name="form1" action="jq.html#test1" method="post">
</form>
<a id="f1_submit" href="#">Form1</a></br>
<form name="form2" action="jq.html#test2" method="post">
</form>
<a id="f2_submit" href="#">Form2</a></br>
<a id="f3_submit" href="#">Form2</a></br>
</body>
</html>
the submitted form always takes the action of the second form? Clicking on f1_submit never submits the first form. but click on f3_submit works fine.
Change History (2)
comment:1 Changed 14 years ago by
| Description: | modified (diff) |
|---|
comment:2 Changed 14 years ago by
| Resolution: | → invalid |
|---|---|
| Status: | new → closed |
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Your selectors are incorrect. Give your forms an id that is the same as the name and just use the id.
Instead of:
$("form:form1").submit();Do this:
$("#form1").submit();Or if you want to stick to the name attribute:
$("form[name=form1]").submit();Selector docs: http://docs.jquery.com/Selectors