show() sometimes uses wrong display type

[jeremy.cloud]

If you call hide() on an element that already has style="display: none", but which has a CSS declared display value that differs from the default, and then later call show() on that element, the resulting display type of the element is the default display value for that element, rather than the display value specified in the CSS rule.

This is a regression in 1.3.*, as it worked correctly in 1.2.6. I have attached a simple test case that demonstrates this bug.

[jeremy.cloud]

Test Case

[jeremy.cloud]

This seems to work as a workaround to this bug:

jQuery.fn.superHide = jQuery.fn.hide;
jQuery.fn.hide = function() {
    return this.each(function() {
        var $this = $(this);
        if ($this.css('display') != 'none') {
            $this.superHide();
        }
    });
};

[Rick Waldron]

Issue no longer exists:

​http://jsfiddle.net/rwaldron/YDhwb/2/

[[email protected]…]

I was able to repro - what does that mean?

​http://jsfiddle.net/mlhDevelopment/YDhwb/3/

[Rick Waldron]

Thanks but that test case only proves that doing the wrong thing produces a "broken" result.