offset returns top/left = 0 for a position: absolute / display: none div element

Reported by:	epsilon68	Owned by:	brandon
Priority:	undecided	Milestone:	1.3
Component:	offset	Version:	1.2.6
Keywords:	offset display none	Cc:
Blocked by:		Blocking:

Description

Offset returns a top / left = 0 for my div that is in position absolute and in display none.

this is blocking me to switch completely from Interface to jQuery-UI

I need to have the transfer between a displayed element to another one not yet visible, fade in after the transfer effect.

Many thanks in advance for your help

and thanks a million for your work !!!

Cheers,

Sylvain Pointeau

Attachments (1)

offset.html (1.0 KB) - added by epsilon68 June 16, 2008 09:18PM UTC.

test case

Change History (5)

Changed November 22, 2008 12:29PM UTC by epsilon68 comment:1

Any feedback? someone is working on it? How can I help you?

Changed January 07, 2009 03:28AM UTC by dmethvin comment:2

resolution:	→ wontfix
status:	new → closed

http://docs.jquery.com/CSS/offset

"The method works only with visible elements."

You could set display:block before calling offset() though.

Changed January 07, 2009 04:44AM UTC by dmethvin comment:3

resolution:	wontfix
status:	closed → reopened

Actually, I'll reopen this and let brandon or others weigh in on whether removing this limit is practical.

Changed March 17, 2009 09:11PM UTC by brandon comment:4

resolution:	→ wontfix
status:	reopened → closed

Checking to see if the element is hidden is to much overhead for an already costly method. We would just be setting it's display to block (like interface was doing) before calculating offset. Just call .show().offset().

Changed January 14, 2014 04:06PM UTC by estaples comment:5

Replying to [comment:4 brandon]: