Opened 5 years ago
Closed 4 years ago
#15201 closed bug (migrated)
.offset() thinks all elements in the ShadowDom are disconnected, and thus as 0,0
| Reported by: | rictic | Owned by: | |
|---|---|---|---|
| Priority: | low | Milestone: | None |
| Component: | offset | Version: | 2.1.1 |
| Keywords: | Cc: | ||
| Blocked by: | Blocking: |
Description
JSBin link to reproduce: http://jsbin.com/tamugo/2/edit (try in Chrome (or Firefox with dom.webcomponents.enabled turned on))
An element that is in the shadow dom appears in some ways to not be contained in the document. .offset() assumes that if the element isn't contained in the document then it's disconnected and returns an offset of {top: 0, left: 0}.
When .offset() checks to see if the element is disconnected it could try walking up the DOM not only by checking .parentNode as .contains() does but also by looking at .host, which is how one travels up from a shadow root into its containing element.
Change History (2)
comment:1 Changed 5 years ago by
| Component: | unfiled → offset |
|---|---|
| Priority: | undecided → low |
| Status: | new → open |
comment:2 Changed 4 years ago by
| Resolution: | → migrated |
|---|---|
| Status: | open → closed |
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Migrated to https://github.com/jquery/jquery/issues/1784