Opened 11 years ago
Closed 11 years ago
#12142 closed bug (invalid)
选择器错误
Reported by: | Owned by: | ||
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Priority: | low | Milestone: | None |
Component: | selector | Version: | 1.7.2 |
Keywords: | Cc: | ||
Blocked by: | Blocking: |
Description
<ul><li style="cursor:pointer;" onclick="GetNodes(this,event)" value="1" >开发部<ul><li style="cursor:pointer;" onclick="GetNodes(this,event)" value="4" >研发一部<ul><li style="cursor:pointer;" onclick="GetNodes(this,event)" value="42" >研发一部-1-1</li></ul></li><li style="cursor:pointer;" onclick="GetNodes(this,event)" value="5" >研发二部<ul><li style="cursor:pointer;" onclick="GetNodes(this,event)" value="28" >研发二部1</li></ul></li><li style="cursor:pointer;" onclick="GetNodes(this,event)" value="47" >开发三部<ul><li style="cursor:pointer;" onclick="GetNodes(this,event)" value="49" >开发三部_2</li></ul></li></ul></li></ul>
上面的代码是我的测试代码。
$("li [value=1]") 不能获取到我要的节点信息 返回值是null 除了value=1以外的节点信息都可以正常获取 我工作的时候用的是1.4.2版本,我测试过1.7.2 也存在这个问题。希望你们能够及时解决这个bug。谢谢。
Change History (1)
comment:1 Changed 11 years ago by
Component: | unfiled → selector |
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Priority: | undecided → low |
Resolution: | → invalid |
Status: | new → closed |
There shouldn't be a space with the tag name and the attribute selector. Try this $("li[value=1]")