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#11913 closed bug (cantfix)
Opened June 14, 2012 06:34PM UTC
Closed June 23, 2012 02:12PM UTC
clone().show() does not revert to original CSS display property, show().clone() does.
Reported by: | pnegahdar@gmail.com | Owned by: | |
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Priority: | undecided | Milestone: | None |
Component: | unfiled | Version: | 1.7.2 |
Keywords: | Cc: | ||
Blocked by: | Blocking: |
Description
TEST: http://jsfiddle.net/bsnxp/1/
What it does:
- Hides the div (you can also start it using display: none on the main div)
- clone().show() replaces the div html with display: block (not original css display: inline-block)
-show().clone() replaces the div html back to original css display property (inline-block)
What I expected it to do:
-clone.show() should behave like show().clone() and return the original css display property (not block). The jquery documentation on show() states: "except that the display property is restored to whatever it was initially"
Attachments (0)
Change History (1)
Changed June 23, 2012 02:12PM UTC by comment:1
resolution: | → cantfix |
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status: | new → closed |
The knowledge of the previous
inline-block
state was stored in the.data()
of the element you cloned, but you did not specify that the *data* should be cloned. You can either clone the data as well or reverse the order of the methods. There is no other place we can keep that information.