#1052 closed bug (fixed)
fadeIn() seems to be broken
| Reported by: | pilyoto | Owned by: | |
|---|---|---|---|
| Priority: | major | Milestone: | 1.1.3 |
| Component: | effects | Version: | 1.1.2 |
| Keywords: | Cc: | ||
| Blocked by: | Blocking: |
Description (last modified by )
used fadeOut() on a div, works as expected. But after using fadeIn() on the same div, it doesn't reappear.
-using latest svn rev 1537
Change History (2)
comment:1 Changed 13 years ago by
comment:2 Changed 13 years ago by
| Description: | modified (diff) |
|---|---|
| need: | → Review |
| Resolution: | → fixed |
| Status: | new → closed |
Fixed in SVN rev [1925].
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Seems that fadeIn() is not changing the display property from display:none to the element's default or whatever was set before the display:none was applied ; instead, it's just changing the element's opacity.