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#1052 closed bug (fixed)
Opened March 16, 2007 08:42AM UTC
Closed May 20, 2007 08:55AM UTC
Last modified June 21, 2007 03:32AM UTC
fadeIn() seems to be broken
| Reported by: | pilyoto | Owned by: | |
|---|---|---|---|
| Priority: | major | Milestone: | 1.1.3 |
| Component: | effects | Version: | 1.1.2 |
| Keywords: | Cc: | ||
| Blocked by: | Blocking: |
Description
used fadeOut() on a div, works as expected. But after using fadeIn() on the same div, it doesn't reappear.
-using latest svn rev 1537
Attachments (0)
Change History (2)
Changed March 18, 2007 05:57PM UTC by comment:1
Changed May 20, 2007 08:55AM UTC by comment:2
| description: | used fadeOut() on a div, works as expected. But after using fadeIn() on the same div, it doesn't reappear.\ \ -using latest svn rev 1537 → used fadeOut() on a div, works as expected. But after using fadeIn() on the same div, it doesn't reappear. \ \ -using latest svn rev 1537 |
|---|---|
| need: | → Review |
| resolution: | → fixed |
| status: | new → closed |
Fixed in SVN rev [1925].
Seems that fadeIn() is not changing the display property from display:none to the element's default or whatever was set before the display:none was applied ; instead, it's just changing the element's opacity.