wrong value for selector property on chained finds with comma in selector

[anonymous]

If I do: var a = jQuery("table:first").find("tr").find('img,a')

I correctly get all the images and links in the rows of the first table.

However, the returned jQuery object has this as the value for its selector property:

console.log(a.selector); "table:first tr img,a"

which is just a concatenation and would not return the same thing at all:

jQuery("table:first tr img,a")

[Rick Waldron]

Thanks for taking the time to contribute to the jQuery project! Please provide a complete reduced test case on jsFiddle to help us assess your ticket!

Additionally, be sure to test against the jQuery Edge version to ensure the issue still exists. To get you started, use this boilerplate: ​http://jsfiddle.net/FrKyN/ Open the link and click to "Fork" (in the top menu) to get started.

[anonymous]

Here is the test: ​http://jsfiddle.net/sf2Fn/3/

[Rick Waldron]

So, which part is not doing what is expected? ​http://gyazo.com/3048146e8db6b69e65a0fddd7e980c8e.png

[anonymous]

The second link should not be red, and the first link should read: "table img, table a" assuming the selector property has any meaning.

[dmethvin]

Don't look at the .selector property, it's not documented to survive traversal methods and is only to be used internally.

[dmethvin]

Duplicate of #6754.

[anonymous]

Thanks!