Ticket #7940 (closed bug: wontfix)
$('aa').find('bb, cc') includes the wrong elements
| Reported by: | korinthe | Owned by: | korinthe |
|---|---|---|---|
| Priority: | low | Milestone: | 1.next |
| Component: | selector | Version: | 1.4.2 |
| Keywords: | Cc: | ||
| Blocking: | Blocked by: |
Description
This is only superficially related to #6754. I am not talking about use of the selector() method at all.
$('aa').find('bb,cc') should find all the elements found by $('aa bb') plus those found by $('aa cc'). Instead it finds $('aa bb') plus $('cc'). Not so useful
Change History
comment:1 Changed 2 years ago by rwaldron
- Owner set to korinthe
- Status changed from new to pending
- Component changed from unfiled to selector
comment:2 Changed 2 years ago by addyosmani
- Priority changed from undecided to low
- Status changed from pending to closed
- Resolution set to wontfix
Thanks for submitting your ticket. We have reproduced a minimal test case of the code you're talking about here Live Test Case, but have determined that there is no documented case of .find() supporting two comma-separated strings. You are however able to use a sting string with as many comma-separated selector values as you wish as this should be more than adequate for most use cases.
Please follow the bug reporting guidlines and use jsFiddle when providing test cases and demonstrations instead of pasting the code in the ticket.
Thanks for taking the time to contribute to the jQuery project! Please provide a reduced jsFiddle test case to help us assess your ticket!
Additionally, test against the latest jQuery release and the jQuery 0 GIT version to ensure the issue still exists. Be Excellent to eachother!