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#4592 closed bug (worksforme)
Opened April 26, 2009 11:44PM UTC
Closed May 04, 2009 12:37AM UTC
Invalid element by specified index
| Reported by: | DelMadman | Owned by: | |
|---|---|---|---|
| Priority: | major | Milestone: | 1.4 |
| Component: | core | Version: | 1.3.2 |
| Keywords: | eq, nt-child | Cc: | |
| Blocked by: | Blocking: |
Description
I have a table with 15 columns, 3rd column is invisible with css property 'display:none'.
The task is to get 13th cell in all rows.
At runtime I know column index and tryed two queries:
1. $("#mytable").find("tr td:eq(13)")
2. $("#mytable").find("tr td:nth-child(13)")
The first query returns certain cell but only from the first row. Against the second query returns invalid cells (12th in my way), but in all rows. I think the reason is in the 3rd invislible column.
As a user I think that both queries should be equals, I mean they should return 13th cell in row no matter it visible or not.
Attachments (0)
Change History (1)
Changed May 04, 2009 12:37AM UTC by comment:1
| resolution: | → worksforme |
|---|---|
| status: | new → closed |
The first case shouldn't be surprising since the docs say
"Matches a single element by its index."http://docs.jquery.com/Selectors/eq#index
The selector
returns all elements that are descendants of a element (all of them) and selects the 13th element.As the docs say, the
selector is 0-based but the selector is 1-based. Does that explain the difference you are seeing in counting cells? You didn't provide a test case so it's hard to know if things are working as they should.It's best to ask about these things on the forums to be sure they're really bugs before opening a ticket. I'll close the ticket for now, but if you have a test case that shows things aren't working as documented just reopen the ticket and attach the file.