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Ticket #4316 (closed bug: worksforme)

Opened 4 years ago

Last modified 4 years ago

Safari 4 Fade Issues

Reported by: whoughton Owned by:
Priority: minor Milestone: 1.4
Component: effects Version: 1.3.2
Keywords: Cc:
Blocking: Blocked by:

Description (last modified by davidserduke) (diff)

 http://www.mixicon.com/tools/jqtest.html

Using fadeIn, FadeOut, fadeTo all create an issue in the Safari 4 beta, I'm not sure if this is Safari's problem or jQuery's.

On that page, Safari shows an error of:

TypeError: Result of expression '(o.fx.step[this.prop]
o.fx.step._default)' [0] is not a function.

Change History

comment:1 Changed 4 years ago by fALk

I can second this bug. Seems to work with build 5528.16 but the latest nightly webkit build 5528.16, r41521 shows above behavior.

comment:2 Changed 4 years ago by whoughton

Submitted this to the webkit bugs as well, considering that it may be a squirrelfish bug (or whatever it's called now).

 https://bugs.webkit.org/show_bug.cgi?id=24471

comment:3 Changed 4 years ago by davidserduke

  • Status changed from new to closed
  • Resolution set to worksforme
  • Description modified (diff)

Seems to work in the release version of Safari 4 and the webkit ticket indicates they made a fix so closing on that basis.

Please follow the  bug reporting guidlines and use  jsFiddle when providing test cases and demonstrations instead of pasting the code in the ticket.

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