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#4316 closed bug (worksforme)
Opened March 09, 2009 07:14PM UTC
Closed October 28, 2009 02:04PM UTC
Safari 4 Fade Issues
| Reported by: | whoughton | Owned by: | |
|---|---|---|---|
| Priority: | minor | Milestone: | 1.4 |
| Component: | effects | Version: | 1.3.2 |
| Keywords: | Cc: | ||
| Blocked by: | Blocking: |
Description
http://www.mixicon.com/tools/jqtest.html
Using fadeIn, FadeOut, fadeTo all create an issue in the Safari 4 beta, I'm not sure if this is Safari's problem or jQuery's.
On that page, Safari shows an error of:
TypeError: Result of expression '(o.fx.step[this.prop]||o.fx.step._default)' [0] is not a function.
Attachments (0)
Change History (3)
Changed March 09, 2009 08:33PM UTC by comment:1
Changed March 10, 2009 03:18AM UTC by comment:2
Submitted this to the webkit bugs as well, considering that it may be a squirrelfish bug (or whatever it's called now).
Changed October 28, 2009 02:04PM UTC by comment:3
| description: | \ http://www.mixicon.com/tools/jqtest.html \ \ Using fadeIn, FadeOut, fadeTo all create an issue in the Safari 4 beta, I'm not sure if this is Safari's problem or jQuery's. \ \ On that page, Safari shows an error of: \ TypeError: Result of expression '(o.fx.step[this.prop]||o.fx.step._default)' [0] is not a function. → http://www.mixicon.com/tools/jqtest.html \ \ Using fadeIn, FadeOut, fadeTo all create an issue in the Safari 4 beta, I'm not sure if this is Safari's problem or jQuery's. \ \ On that page, Safari shows an error of: \ TypeError: Result of expression '(o.fx.step[this.prop]||o.fx.step._default)' [0] is not a function. |
|---|---|
| resolution: | → worksforme |
| status: | new → closed |
Seems to work in the release version of Safari 4 and the webkit ticket indicates they made a fix so closing on that basis.
I can second this bug. Seems to work with build 5528.16 but the latest nightly webkit build 5528.16, r41521 shows above behavior.