Side navigation
#4246 closed bug (fixed)
Opened February 25, 2009 03:53PM UTC
Closed December 09, 2009 04:49PM UTC
Results from .children() should be sorted in order
Reported by: | john | Owned by: | |
---|---|---|---|
Priority: | major | Milestone: | 1.4 |
Component: | core | Version: | 1.3.2 |
Keywords: | Cc: | ||
Blocked by: | Blocking: |
Description
The results from doing $("div").children("p") should be identical to doing $("div > p") (right now the results are unique but not necessarily in the correct sorted order).
Attachments (0)
Change History (4)
Changed February 25, 2009 04:01PM UTC by comment:1
description: | The results from doing $("div").find("p") should be identical to doing $("div p") (right now the results are unique but not necessarily in the correct sorted order). → The results from doing $("div").children("p") should be identical to doing $("div > p") (right now the results are unique but not necessarily in the correct sorted order). |
---|---|
summary: | Results from .find() should be sorted in order → Results from .children() should be sorted in order |
Changed February 25, 2009 11:52PM UTC by comment:2
Are you talking to yourself again, John? Did you mean to close this ticket?
Changed March 13, 2009 02:33AM UTC by comment:3
Yes, I'm talking to myself. I just re-wrote the the ticket summary and description to match the new problem. I'll have to tackle this at some point.
Changed December 09, 2009 04:49PM UTC by comment:4
resolution: | → fixed |
---|---|
status: | new → closed |
This has been resolved in 1.4.
Actually, this doesn't seem to be an issue for .find(), they're already in document order, nevermind.
This would be an issue for .children(), though.