.show() ignores .visibility

[yereth]

When .show() is called on an element which has 'visibility: hidden', it simply ignores this. I'd say .show() is a way to simply tell the element to show itself! So therefore I suggest the following solution to make .show() also work on invisible elements;

	show: function(speed,callback){
		return speed ?
			this.animate({
				height: "show", width: "show", opacity: "show"
			}, speed, callback) :
			
			this.filter(":hidden").each(function(){
				this.style.display = this.oldblock ? this.oldblock : "";
				if ( jQuery.css(this,"display") == "none" )
					this.style.display = "block";
				if ( jQuery.css(this,"visibility") == "hidden" )
					this.style.visibility = "visible";
			}).end();
	},

[brandon]

The show and hide methods deal only with the display property.

[yereth]

By now the discussion has continued on the jquery dev group.

Please reconsider. Brandon has already replied. See the following 2 posts for the discussion:  http://groups.google.com/group/jquery-dev/browse_thread/thread/6ca936d7e0ebad3c  http://groups.google.com/group/jquery-dev/browse_thread/thread/b747f9a937ed93d3

[dmethvin]

Elements can be hidden by changing display, visibility, opacity, or by positioning them out of the viewport (e.g., large negative margin). Up to this point hide/show have only dealt with display. Has there been a problem with that interpretation?

[dmethvin]

Since this is long-documented behavior that would likely break existing code if changed, I'll close this ticket.