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Ticket #10986 (closed feature: invalid)
Full page source
| Reported by: | matjaz.horvat@… | Owned by: | |
|---|---|---|---|
| Priority: | low | Milestone: | None |
| Component: | misc | Version: | 1.7.1 |
| Keywords: | Cc: | ||
| Blocking: | Blocked by: |
Description
There is currently no easy way of displaying full website source (rendered). Of course, one can use $("html").html(), but in this case DOCTYPE and <html> tag are omitted.
Change History
comment:2 Changed 19 months ago by sindresorhus
- Priority changed from undecided to low
- Resolution set to invalid
- Status changed from new to closed
- Component changed from unfiled to misc
This is a bug tracker, not a forum. Try asking in the jQuery forum or on StackOverflow.
You could do something like this:
console.log( '<!doctype html>' + document.documentElement.outerHTML );
Please follow the bug reporting guidlines and use jsFiddle when providing test cases and demonstrations instead of pasting the code in the ticket.
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To display full page source, currently one has to do something like this:
var dt = document.doctype, public = (dt.publicId) ? ' PUBLIC "' + dt.publicId + '"' : "", system = (dt.systemId) ? ' "' + dt.systemId + '"': "", doctype = '<!DOCTYPE ' + dt.name + public + system + '>', html = '<html'; $($("html")[0].attributes).each(function() { html += ' ' + this.name + '="' + this.nodeValue + '"'; }); var fullSource = doctype + "\n" + html + ">\n" + $("html").html() + "\n</html>";