var jq = $("<selector1>") // selects more than one element
jq.replaceAll("<selector2>") 

only the first matched element from jq will show up as the replacement for "<selector2>"

Possible Fix:  See Attachment



jQuery.each({
	appendTo: "append",
	prependTo: "prepend",
	insertBefore: "before",
	insertAfter: "after",
	replaceAll: "replaceWith"
}, function(name, original){
	jQuery.fn[ name ] = function( selector ) {
		var ret = [], insert = jQuery( selector );

		for ( var i = 0, l = insert.length; i < l; i++ ) {
			var elems = (i > 0 ? this.clone(true) : this).get();
			//jQuery.fn[ original ].apply( jQuery(insert[i]), elems );	// this is wrong
			jQuery.fn[ original ].call( jQuery(insert[i]), elems );	// this is what it should be
			ret = ret.concat( elems );
		}

		return this.pushStack( ret, name, selector );
	};
});